Question

A boy has 82 cents in pennies and quarters. He has 4 more pennies than quarters. How many of each type of coin does he have?

Answer 1

The boy has 3 quarters and 7 pennies.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's say that the number of quarters the boy has is q. Since he has 4 more pennies than quarters, the number of pennies he has is q + 4. We know that 1 quarter is equal to 25 cents and 1 penny is equal to 1 cent. So, the total value of the coins can be expressed as 25q + (q + 4) = 82.

Simplifying the equation, we have 25q + q + 4 = 82.

Combining like terms, we get 26q + 4 = 82.

Subtracting 4 from both sides, we have 26q = 78.

Dividing both sides by 26, we find that q = 3. Therefore, the boy has 3 quarters and 3 + 4 = 7 pennies.

Answer 2

3 quarters and 7 pennies

Step-by-step explanation:

You can write equations, but you can also use the trial and error method.

Guess 1:

1 quarter = 25 cents

82 - 25 = 57

57 pennies = 57 cents

25 cents + 57 cents = 82 cents

57 - 1 = 56

He has 56 more pennies than quarters, so this is not the answer.

Guess 2:

2 quarters = 50 cents

82 - 50 = 32

32 pennies = 32 cents

50 cents + 32 cents = 82 cents

32 - 2 = 30

He has 30 more pennies than quarters, so this is not the answer.

Guess 2:

3 quarters = 75 cents

82 - 75 = 7

7 pennies = 7 cents

75 cents + 7 cents = 82 cents

7 - 3 = 4

He has 4 more pennies than quarters, so this is the answer.

Answer: 3 quarters and 7 pennies