40.0k views
0 votes
A boy has 82 cents in pennies and quarters. He has 4 more pennies than quarters. How many of each type of coin does he have?

2 Answers

3 votes

Final answer:

The boy has 3 quarters and 7 pennies.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's say that the number of quarters the boy has is q. Since he has 4 more pennies than quarters, the number of pennies he has is q + 4. We know that 1 quarter is equal to 25 cents and 1 penny is equal to 1 cent. So, the total value of the coins can be expressed as 25q + (q + 4) = 82.

Simplifying the equation, we have 25q + q + 4 = 82.

Combining like terms, we get 26q + 4 = 82.

Subtracting 4 from both sides, we have 26q = 78.

Dividing both sides by 26, we find that q = 3. Therefore, the boy has 3 quarters and 3 + 4 = 7 pennies.

User Patrick Barr
by
7.3k points
4 votes

Answer:

3 quarters and 7 pennies

Step-by-step explanation:

You can write equations, but you can also use the trial and error method.

Guess 1:

1 quarter = 25 cents

82 - 25 = 57

57 pennies = 57 cents

25 cents + 57 cents = 82 cents

57 - 1 = 56

He has 56 more pennies than quarters, so this is not the answer.

Guess 2:

2 quarters = 50 cents

82 - 50 = 32

32 pennies = 32 cents

50 cents + 32 cents = 82 cents

32 - 2 = 30

He has 30 more pennies than quarters, so this is not the answer.

Guess 2:

3 quarters = 75 cents

82 - 75 = 7

7 pennies = 7 cents

75 cents + 7 cents = 82 cents

7 - 3 = 4

He has 4 more pennies than quarters, so this is the answer.

Answer: 3 quarters and 7 pennies

User David Ward
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories