To solve this problem we will apply the concept of gravity as a function of density, the universal gravity constant and the radius of the Planet to be investigated. This relationship is written mathematically as

Here
G = Universal gravitational constant
= Density
R = Radius
Given acceleration due to gravity on Venus's surface is

and Radius of Venus is

Using the previous equation and rearranging to find the density we have,



Therefore the average density of Venus is
