Question

How would you solve this
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Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}♨`

Let's write the equation in standard form ~

`\qquad \sf  \dashrightarrow \: {x}^(2) + {y}^(2) - 2y - 15 = 0`

`\qquad \sf  \dashrightarrow \:(x ){ }^(2) + {y}^(2) - 2y = 15`

`\qquad \sf  \dashrightarrow \:(x ){ }^(2) + {y}^(2) - 2y + 1 = 15 + 1`

`\qquad \sf  \dashrightarrow \:(x ){ }^(2) +( {y}^{} - 1 ) {}^(2) = 16`

Now, it's the required form of circle ~