Answer:
Therefore 40 milliliter of 50% fungicide solution is required
Therfore 60 milliliter of 10% fungicide solution is required
Explanation:
i) Let the 10% fungicide solution have x milliliter and the 50% fungicide solution have y milliliter.
ii) Therefore 10x + 50y = 26(x + y)
x + y = 100
iii) form the first equation in ii) we get
16 x = 24 y Therefore
![x = (24)/(16) y = (3)/(2) y](https://img.qammunity.org/2021/formulas/mathematics/middle-school/immn55v9y6qjtyqa11b4km7a0j60c0wlrm.png)
iv) substituting the value obtained in iii) in the second equation in ii) we get
![(3)/(2) y + y = (5)/(2) y = 100](https://img.qammunity.org/2021/formulas/mathematics/middle-school/c2dnj8g2axpnwwblnkvb3k6i3c5fcpomqy.png)
Therefore y = 100 ÷ 2.5 = 40 milliliter
Therfore x = 100 - 40 = 60 milliliter