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A package of aluminum foil is 68.6 yd long, 12 in. wide, and 0.00035 in. thick. If aluminum has a density of 2.70 g/cm3, what is the mass, in grams, of the foil?

1 Answer

3 votes

Answer:

The answer to your question is mass = 455.6 grams

Step-by-step explanation:

Data

Dimensions = 68.6 yd x 12 in x 0.00035 in

density = 2.70 g/cm³

mass = ?

Process

1.- Convert dimensions to cm

1 yd ---------------- 91.44 cm

68.6 yd ------------ x

x = (68.6 x 91.44) / 1

x = 6227 cm

1 in ----------------- 2.54 cm

12 in --------------- x

x = (12 x 2.54) / 1

x = 30.48 cm

1 in -------------- 2.54

0.00035 in ------------- x

x = (0.00035 x 2.54) / 1

x = 0.000889 cm

2.- Find the volume of the foil

V = 6227 x 30.48 x 0.000889

V = 168.73 cm³

3.- Find the mass of the foil

mass = density x volume

mass = 2.70 x 168.73

mass = 455.6 g

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