Question

How many milliliters of 10.0 M HCl ( aq ) are needed to prepare 790.0 mL of 1.00 M HCl ( aq )

Answer 1

79.0 mL

Step-by-step explanation:

Given data

• Initial concentration (C₁): 10.0 M

• Initial volume (V₁): ?

• Final concentration (C₂): 1.00 M

• Final volume (V₂): 790.0 mL

In order to find the volume required of the concentrated solution, we will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 1.00 M × 790.0 mL/10.0 M

V₁ = 79.0 mL