Question

Find the equation for the line that passes through (-1, -2) and (4, 3). Is the

point (3, 1) on this line?

Answer 1

The answer to your question is a) y = x - 1 b) the point is not on the line

Explanation:

Data

A ( -1, -2)

B (4, 3)

C ( 3, 1)

Process

1.- Find the slope of the line (m)

Formula

m =
`(y2 - y1)/(x2 - x1)`

Substitution

m =
`(3 + 2)/(4 + 1) = (5)/(5) = 1`

2.- Find the equation of the line

Formula

y - y1 = m(x - x1)

Substitution

y + 2 = 1(x + 1)

Solve for y

y = x + 1 - 2

y = x - 1

- Prove that the point (3, 1) is on the line

1 = 3 - 1

1 = 2

The point is not on the line because 1 ≠ 2