Question

Solve for x and round if necessary

Answer 1

`\displaystyle 1`

Explanation:

`\displaystyle (x)/(0,6) = csc\:37 \hookrightarrow 0,6csc\:37 = x \hookrightarrow 0,9969840846... = x \\ \\ 1 ≈ x`

OR

`\displaystyle (0,6)/(x) = sin\:37 \hookrightarrow xsin\:37 = 0,6 \hookrightarrow (0,6)/(sin\:37) = x \hookrightarrow 0,9969840846... = x \\ \\ 1 ≈ x`

Information on trigonometric ratios

`\displaystyle (OPPOCITE)/(HYPOTENUSE) = sin\:θ \\ (ADJACENT)/(HYPOTENUSE) = cos\:θ \\ (OPPOCITE)/(ADJACENT) = tan\:θ \\ (HYPOTENUSE)/(ADJACENT) = sec\:θ \\ (HYPOTENUSE)/(OPPOCITE) = csc\:θ \\ (ADJACENT)/(OPPOCITE) = cot\:θ`

I am joyous to assist you at any time.

Answer 2

`\qquad\qquad\huge\underline{{\sf Answer}}☂`

Let's solve ~

`\qquad \sf  \dashrightarrow \: \sin(37 \degree) = (0.6)/(x)`

`\qquad \sf  \dashrightarrow \: (3)/(5) = (0.6)/(x)`

`\qquad \sf  \dashrightarrow \: 3x = 5 * 0.6`

`\qquad \sf  \dashrightarrow \: x = 3 / 3`

`\qquad \sf  \dashrightarrow \:x = 1`

Therefore, the required value of x is 1