Answer:
The question is incomplete, below is the complete question
"The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ), where y is in m and t is in s.
A) What is the frequency of this wave?
B) What is the wavelength of this wave?
C) What is the speed of this wave?"
Answers:
a.
![f=(30)/(\pi )Hz\\](https://img.qammunity.org/2021/formulas/physics/high-school/wwd4cr9x355djjaih8vl8oxkdxihicegou.png)
b.
![wavelength=(\pi )/(3.1)m \\](https://img.qammunity.org/2021/formulas/physics/high-school/szwcxd0lcqzkqypc07xvhd3bu9vp34971i.png)
c.
![v=9.68m/s](https://img.qammunity.org/2021/formulas/physics/high-school/4xm7ira7zrtzgn88rnqo3xof70m2cy4uwl.png)
Step-by-step explanation:
The equation of a wave is represented as
![D(x,t)=Asin(kx+wt) \\](https://img.qammunity.org/2021/formulas/physics/high-school/d825ewn33huyotdow7quyz1cfqy9cn656g.png)
Where A=amplitude
w=angular frequency=2πf
K=wave numbers =2π/λ
since we re giving he equation D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ),
we can compare and get the value for the wave number and angular frequency.
By comparing we have
w=60rads/s
k=6.20
a. to determine the frequency, from the expression fr angular wave frequency we have
w=2πf hence
f=w/2π
if we substitute we arrive at
![f=(60)/(2\pi )\\f=(30)/(\pi )Hz\\](https://img.qammunity.org/2021/formulas/physics/high-school/qpl3jmaw42pjde4q3i4sdi08763up4o4b2.png)
b. to determine the wave length, we use
![k=(2\pi )/(wavelength) \\k=6.2\\wavelength=(2\pi )/(k) \\wavelength=(2\pi )/(6.2) \\wavelength=(\pi )/(3.1)m \\](https://img.qammunity.org/2021/formulas/physics/high-school/epowndrtecc10bu29jtm66dsovdvje27xq.png)
c. the wave speed v is express as the product of the frequency and the wavelength. Hence
![v=frequency*wavelength \\v=(30)/(\pi ) *(\pi )/(3.1)\\ v=9.68m/s](https://img.qammunity.org/2021/formulas/physics/high-school/jmloj5xkth41gy1t9rix40ngvj6tzovy2s.png)