Question

1.5 kg ball is thrown upward with a velocity of 6 m/s. a. What is the kinetic energy of the ball as it is thrown upward? b. What is the gravitational potential energy of the ball when it reaches its highest point? c. To what height above the thrower’s hand will the ball rise?

Answer 1

a) 27 Joules

b) 27 Joules

c) 1.8m

Step-by-step explanation:

m = 1.5kg

v = 6m/s

KE = 0.5 * m * v * v

KE = 0.5 * 1.5 * 6 * 6

= 27J

PE = KE = 27J (Kinetic Energy is converted to Potential Energy at the maximum height. This is one of the applications of conservation of energy)

PE = 27 = mgh where g is the acceleration due to gravity of the earth and it has a constant of
`10m/s^(2)`

solving for h which will be the maximum height the ball reaches, we have

h = 27/(1.5*10)

h = 1.8m