Question

A and B play a game in which they alternately toss a pair of dice. The one who is first to get a total of 7 wins the game. Find the probability that (a) the one who tosses first wins the game

Answer 1

Answer: the probability that the first toss wins is:

P = 1/6 or 0.1667

Explanation:

A die has six sides (that is 6 outcome per die)

For a pair of dice:

The Total number of possible outcomes = 6 × 6 = 36

The possible outcomes of 7 is:

(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)

= 6

The probability P of getting 7 is:

P = number of possible outcomes of 7/total number of possible outcomes

P = 6/36 = 1/6

The probability that the first toss wins

P = 1/6 or 0.1667