Question

A sample of coarse aggregate has an oven dry weight of 1034.0 g and a moisture content of 4.0 %. The saturated surface dry weight is 1048.9g and the weight of the aggregate in water is 675.6 g. Determine using phase volume relationships: a) Apparent Specific Gravity (GA) b) Bulk Specific Gravity (GB) c) Bulk Specific Gravity SSD (GB (SSD)) d) Absorption, % e) Bulk Volume

Answer 1

Apparent Specific Gravity = 2.88

bulk specific gravity = 2.76

Bulk Specific Gravity SSD = 2.80

absorption = 1.44%

bulk volume = 373.3

Step-by-step explanation:

given data

oven dry weight A = 1034.0 g

moisture content = 4.0 %

saturated surface dry weight B = 1048.9 g

weight of the aggregate in water C = 675.6 g

solution

we get here Apparent Specific Gravity that is express as

Apparent Specific Gravity =
`(A)/(A-C)` ..........1

put here value

Apparent Specific Gravity =
`(1034)/(1034-675.6)`

Apparent Specific Gravity = 2.88

and

now we get bulk specific gravity that is

bulk specific gravity =
`(A)/(B-C)` ...................2

put here value

bulk specific gravity =
`(1034)/(1048.9-675.6)`

bulk specific gravity = 2.76

and

now we get Bulk Specific Gravity SSD

Bulk Specific Gravity SSD =
`(B)/(B-C)` ............3

Bulk Specific Gravity SSD =
`(1048.9)/(1048.9-675.6)`

Bulk Specific Gravity SSD = 2.80

and

now absorption will be here as

absorption =
`(B-A)/(A)` × 100% ................4

absorption =
`(1048.9-1034)/(1034)` × 100%

absorption = 1.44%

and

last we get bulk volume that is

bulk volume =
`(weight\ displce\ water)/(density\ water )`

bulk volume =
`(1048.9-675.6)/(1)`

bulk volume = 373.3