The question is incomplete, here is the complete question:
A chemistry student needs 15.00 g of 2-bromobutane for an experiment. He has available 220. g of a 30.0 % w/w solution of 2-bromobutane in ethanol. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.
Answer: The mass of solution, the student should use is 50.0 grams
Step-by-step explanation:
We are given:
30.0 % (w/w) of 2-bromobutane
This means that 30 grams of 2-bromobutane is present in 100 g of solution
Mass of solution given = 220. g
Mass of 2-bromobutane, the student needs = 15.00 g
Calculating the mass of 2-bromobutane in given amount of solution:
![\Rightarrow 220* (30)/(100)=66g](https://img.qammunity.org/2021/formulas/chemistry/college/zac0c7fdoteti5xf2i8coh2kfs0jatr4xp.png)
To calculate the mass of solution, we use unitary method:
If 66 grams of 2-bromobutane is present in 220 grams of solution
So, 15 grams of 2-bromonutane will be present in
of solution
Hence, the mass of solution, the student should use is 50.0 grams