Answer:
![14m/s^2](https://img.qammunity.org/2021/formulas/physics/college/1bnh9nh4l8uyonmcqkiqz6xq9teaqqrnc2.png)
Step-by-step explanation:
Initial speed of car=0 Km/h=
![0m/s](https://img.qammunity.org/2021/formulas/physics/college/dsx30xk4nfldxfw7fpukds2us57wf7cx6h.png)
Final speed of car=
![100km/h=100* (5)/(18)=(250)/(9) m/s](https://img.qammunity.org/2021/formulas/physics/college/60i1rjilfvgz05oyrpesdr5dxdbce1vufp.png)
By using
![1km/h=(5)/(18)m/s](https://img.qammunity.org/2021/formulas/physics/college/gojnw0rnk7kkljvyynrf1b4c0p6zs7708y.png)
Time taken by car=2 s
We know that
Acceleration=
![a=(v-u)/(t)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/omw5pwjk5rbm6210mvnr9h5tg65v3cs0wf.png)
Where v=Final velocity of object
u=Initial velocity of object
t=Time taken by object
Using the formula
Acceleration of car=
![((250)/(9)-0)/(2)=(250)/(9* 2)=13.9 m/s^2\approx 14m/s^2](https://img.qammunity.org/2021/formulas/physics/college/omgi9iodv13gyiwm8sa1wm2ex8h2if6cje.png)
Hence, the acceleration of car about=
![14m/s^2](https://img.qammunity.org/2021/formulas/physics/college/1bnh9nh4l8uyonmcqkiqz6xq9teaqqrnc2.png)