Question

What are the solutions to the equation?

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}♪`

Let's solve ~

`\qquad \sf  \dashrightarrow \:f(x) = g(x)`

`\qquad \sf  \dashrightarrow \:x + 2 = - {x}^(2) + 4`

`\qquad \sf  \dashrightarrow \: {x}^(2) + x + 2 - 4 = 0`

`\qquad \sf  \dashrightarrow \: {x}^(2) + x - 2 = 0`

`\qquad \sf  \dashrightarrow \: {x}^(2) + 2x - x - 2 = 0`

`\qquad \sf  \dashrightarrow \:x(x + 2) - (x + 2) = 0`

`\qquad \sf  \dashrightarrow \:(x + 2)(x - 1) = 0`

Hence, x = -2 or x = 1