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What is the best approximate value for the elastic potential energy (EPE) of the spring elongated by 7.0 meters?

1.5 J
11 J
37 J
74 J

1 Answer

2 votes

Answer:

C. 37 J

Step-by-step explanation:

This problem was given with a graph showing that when the spring was elongated to 7 m, the force was approximately 11 N. Seeing as the EPE is calculated by finding the area under the graph and that the area of a triangle is found by using A = 1/2bh, you can see that the givens are b = 7 m & h = 11 N. This means that the the EPE = 1/2 * 7 m * 11 N, which is 38.5N*m. Joules are also represented by N*m so that simplifies to J and seeing as they asked for an approximation, C is the best choice! :)

User Vijay Kumbhar
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