Answer:
a) (y+ Oz)
b) (ab + ac)(abc + cd + ce)
Explanation:
a) xy + xOz (First find the common factor between xy and xOz, and it is x as it appears in both xy and xOz. Factoring out x will result in
x(y+ Oz)
There are no more common factors thus the answer is x(y + Oz)
Since the question was asking after removing redundant terms it will on be y + Oz
b) (ab0 f + a 0 cf)(a 0 bcf + c 0 f(d + e)) simplfying the expression
(ab0 f + a 0 cf)(aObcf + cOfd + cOfe) common factor Of is factored out as below
Of[ (ab + ac)(abc + cd + ce) ] therefore after removing redundant terms the answer is (ab + ac)(abc + cd + ce)