Answer:
![T_f=57.21\ ^(\circ)C](https://img.qammunity.org/2021/formulas/physics/college/pw1qgqpgeg65x0kuxihhtdr6ionipsbvb9.png)
Step-by-step explanation:
Given:
- mass of aluminium,
![m_a=0.2\ kg](https://img.qammunity.org/2021/formulas/physics/college/snic3qb38e0s8orpch2g79td63e7wnh1k5.png)
- initial temperature of the aluminium cylinder,
![T_(ia)=-20\ ^(\circ)C](https://img.qammunity.org/2021/formulas/physics/college/t9bexmluz67j5ggyiy98m96g51m4zndxzg.png)
- mass of coffee,
![m_c=0.5\ kg](https://img.qammunity.org/2021/formulas/physics/college/q95snib79f0hr8n8i934o1r30h5xnfo5of.png)
- initial temperature of coffee,
![T_(ic)=85\ ^(\circ)C](https://img.qammunity.org/2021/formulas/physics/college/p2inb4peyzk82km16jkbwl6zlq4lvblkhk.png)
- specific heat of coffee (assuming water),
![c_w=1000\ J.kg^(-1).^(\circ)C^(-1)](https://img.qammunity.org/2021/formulas/physics/college/8kmqf0e9kihfciwyh2vg0okcs6p8zl5emu.png)
- specific heat of aluminium,
![c_a=900\ J.kg^(-1).^(\circ)C^(-1)](https://img.qammunity.org/2021/formulas/physics/college/mfyr9vpez6h7agw2ly4hp04ckxgvcab3fz.png)
When the coffee and the aluminium cylinder come in contact then heat released by the coffee is equal to the heat gained by the aluminium.
Mathematically:
![Q_c=Q_a](https://img.qammunity.org/2021/formulas/physics/college/alks0oq7vt6w69uyr910q5ymp7rqs2ur30.png)
![m_c.c_w. (T_(ic)-T_f)=m_a.c_a.(T_f-T_(ia))](https://img.qammunity.org/2021/formulas/physics/college/x5wv6vjmeydqxswp4cq2pgfnx2epbnj8db.png)
![0.5* 1000* (85-T_f)=0.2* 900* (T_f-(-20))](https://img.qammunity.org/2021/formulas/physics/college/j5uph7t2jt1crhwuhdqnjtf09451gqb2h9.png)
![42500-500* T_f=180* T_f+3600](https://img.qammunity.org/2021/formulas/physics/college/m4uf7dfuw184vaox8fvkq80e4r72p9bnjj.png)
is the final temperature of agreement.