Answer:
1315789.47368 lines/m
Step-by-step explanation:
m = Order = 1
= 1 For maximum condition
= Wavelength = 760 nm maximum
From Rayleigh criteria we have the expression for the gap
![d=(m\lambda)/(sin\theta)\\\Rightarrow d=(1* 760)/(1)\\\Rightarrow d=760\ nm](https://img.qammunity.org/2021/formulas/physics/high-school/eev043rt76vgg1sn7lhd6a0bqwf8r0s2v8.png)
The number of lines is the reciprocal of the slit distance
![n=(1)/(d)\\\Rightarrow n=(1)/(760* 10^(-9))\\\Rightarrow n=1315789.47368\ /m](https://img.qammunity.org/2021/formulas/physics/high-school/eyf1ichl71g3nn7czyfthbmnkpwv2vlgzv.png)
The number of lines is 1315789.47368 per meter