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Find the missing term.
The quotient of -8x2y3 ÷ xy is same as the product of 4xy and .

1 Answer

4 votes

Missing term = –2xy

Solution:

Let us first find the quotient of
-8x^2y^3 / xy.


-8x^2y^3 / xy=(-8x^2y^3 )/(xy)


=(-8* x* x* y* y* y)/(xy)

Taking common term xy outside in the numerator.


=(xy(-8* x* y* y))/(xy)

Both xy in the numerator and denominator are cancelled.


=-8xy^2

Thus, the quotient of
-8x^2y^3 / xy is
-8xy^2.

Given the quotient of
-8x^2y^3 / xy is same as the product of 4xy and ____.


-8xy^2=4xy × missing term

Divide both sides by 4xy, we get

⇒ missing term =
(-8xy^2)/(4xy)

Cancel the common terms in both numerator and denominator.

⇒ missing term = –2xy

Hence the missing term of the product is –2xy.

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