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36(1/3)^n-1 first five term of the sequence

User Annachiara
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Answer:

Explanation:

first term: put n = 1

36(1/3)^n-1 = 36(1/3)^1-1 =12 - 1 = 11

2nd term: put n = 2

36(1/3)^n-1 = 36(1/3)^2-1 = 19.784

3rd term: put n = 3

36(1/3)^n-1 = 36(1/3)^3-1 = 0.3333

4th term: put n = 4

36(1/3)^n-1 = 36(1/3)^4-1 = -0.5555

5th term: put n = 5

36(1/3)^n-1 = 36(1/3)^5-1 =-0.85185

User Gelatin
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