Question

To navigate, a porpoise emits a sound wave that has a wavelength of 3.3 cm. The speed at which the wave travels in seawater is 1522 m/s. Find the period of the wave.

Answer 1

`2.2* 10^(-5) s`

Step-by-step explanation:

We are given that

The wavelength of sound wave=
`\lambda=3.3 cm=3.3* 10^(-2)m/s`

1 cm/s=
`10^(-2)m/s`

Speed of sound wave,v=
`1522 m/s`

We have to find the period of the wave.

We know that

Frequency=
`\\u=(v)/(\lambda)`

Using the formula

Frequency =
`(1522)/(3.3* 10^(-2))=4.6* 10^(4)` Hz

Time period=
`(1)/(4.6* 10^4)=0.22* 10^(-4)* (10)/(10^1)=2.2* 10^(-4-1)=2.2* 10^(-5)s`

Using identity:
`(a^x)/(a^y)=a^(x-y)`

Hence, the time period of the wave=
`2.2* 10^(-5) s`