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Find the magnitude of the electric force on a 2.0 uC charge in a 100n/C electric field.

1 Answer

2 votes

Answer:

Electric force will be equal to
2* 10^(-4)N

Step-by-step explanation:

We have given charge
q=2\mu C=2* 10^(-6)C

Electric field will be
E=100N/C

We have to find the magnitude of force

Electric force is the multiplication of electric field and charge

So electric force
F=qE=2* 10^(-6)* 100=2* 10^(-4)N

Electric force will be equal to
2* 10^(-4)N

User Max Seelemann
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