Question

Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 9.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol.

Answer 1

Answer: The number of electrons in the given amount of silver are
`2.36* 10^(24)`

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Given mass of silver = 9.0 g

Molar mass of silver = 107.87 g/mol

Putting values in above equation, we get:

`\text{Moles of silver}=(9.0g)/(107.87g/mol)=0.0834mol`

We are given:

Number of electrons in one atom of silver = 47

According to mole concept:

1 mole of an element contains
`6.022* 10^(23)` number of particles

So, 0.0834 moles of silver contains
`(47* 0.0834* 6.022* 10^(23))=2.36* 10^(24)` number of electrons

Hence, the number of electrons in the given amount of silver are
`2.36* 10^(24)`