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On average, an adult person breathes in about 6 liters of air per minute. Assuming atmospheric pressure and 20°C air temperature, estimate the mass of air in kilograms that a person breathes in per day.

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The problem can be covered from different methods for development. I will approximate it by the proximity method. We know that the person breathes about 6 liters per minute, that is
6 * 10 - 3 m ^ 3 / min (Recall that
1L = 1 * 10 - 3 m ^ 3)

Given the conditions, we have that at atmospheric pressure with a temperature of 20 ° C the air density is
1.24kgm ^ 3

Therefore, from the density ratio, the mass would be


\rho = (m)/(V)\rightarrow m = \rho \dot{V}

Here,

m = mass per time unit

V = Volume per time unit


\rho = Density

We have


m = (6*10^(-3)m^3 / min )(1.24kg/m^3 )


m= 7.44*10^(-3) kg/ min

Using the conversion factor from minutes to days,


m= 7.44*10^(-3) kg/ min((60min)/(1hour))((24 hours)/(1day ))


m = 10.7136kg/day

Therefore he mass of air in kilograms that a person breathes in per day is 10.7136kg

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