Question

How many liters of a 20% solution of acid should be added to 10 liters of a 30% solution of acid to obtain a 25% solution?

_____ liters



10 urgent points

plz help

Answer 1

10

Explanation:

Answer 2

10 liters

Explanation:

Let

x ----> liters of a 20% solution of acid

we know that

The number of liters of a 20% solution of acid, multiplied by 0.20 (20% in decimal form) plus 10 liters of a 30% solution of acid multiplied by 0.30 (30% in decimal form) must be equal to the amount of (x+10) liters multiplied by 0.25 (25% in decimal form)

so

The linear equation that represent this problem is equal to

`0.20x+0.30(10)=0.25(x+10)`

solve for x

`0.20x+3=0.25x+2.5\\0.25x-0.20x=3-2.5\\0.05x=0.5\\x=10\ L`