197k views
0 votes
The Kelvin temperature of a sample of 678 cm3 ammonia gas is doubled, what is
the new volume?

User GRZa
by
8.4k points

1 Answer

6 votes

The new pressure will be

1000 L

, rounded to one significant figure.

Step-by-step explanation:

Boyle's law states that when a gas is held at a constant temperature and mass in a closed container, the volume and pressure vary inversely. The equation to use is

P

1

V

1

=

P

2

V

2

.

Given

V

1

=

200

mL

×

1

L

1000

mL

=

0.2 L

P

1

=

700 mmHg

V

2

=

100

mL

×

1

L

1000

mL

=

0.1 L

Unknown

P

2

Equation

P

1

V

1

=

P

2

V

2

Solution

Rearrange the equation to isolate

P

2

and solve.

P

2

=

P

1

V

1

V

2

P

2

=

(

700

mmHg

×

0.2

L

)

0.1

L

=

1400 L

, which must be rounded to

1000 L

because all of the measurements have only one significant figure.

Answer link

User JustGettinStarted
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.