Answer:
Option D.
![2(x+4)-x=11](https://img.qammunity.org/2021/formulas/mathematics/middle-school/32kasic7szoangdal2caw0epptghcivbzb.png)
Explanation:
Let
x ----> the smaller number
y ----> the larger number
we know that
The larger number is twice the value of 4 more than the smaller number
----> equation A
Their difference is 11
----> equation B
substitute equation A in equation B
![2(x+4)-x=11](https://img.qammunity.org/2021/formulas/mathematics/middle-school/32kasic7szoangdal2caw0epptghcivbzb.png)
Solve for x
![2x+8-x=11\\x=11-8\\x=3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/upopx2vilvo9jhxhtlspoj0ok2l6qoslz9.png)
Find the value of y
![y=2(3+4)=14](https://img.qammunity.org/2021/formulas/mathematics/middle-school/z4hr0bx2c0iril3d7dqtzfxc81f6iasjdq.png)
therefore
The numbers are 3 and 14