Question

Given g (x)=-x^2+10x-3
Find g (-3)

Answer 1

The value of g(x) at x=-3 is -42

That is g(-3)=-42

Explanation:

Given that the function g is defined by
`g(x)=-x^2+10x-3`

To find the value of g(-3) :

That is to find the value of g(x) at x=-3 :

`g(x)=-x^2+0x-3`

Put x=-3 in the above function we get

`g(-3)=-(-3)^2+10(-3)-3`

`=-(9)-30-3`

`=-9-33`

`=-42`

Therefore g(-3)=-42

The value of g(x) at x=-3 is -42

That is g(-3)=-42