Question

Sandy is upgrading her Internet service. Fast Internet charges $45 for installation and $49.45 per month.

Quick Internet has free installation but charges $56.95 per month.
Part 1 out of 2
Complete the equation that can be used to find the number of months after which the Internet service
would cost the same. Use the variable x to represent the number of months of Internet service purchased.
The equation is
___+___=___

Answer 1

x = 6 months.

The equation is given by $45 + ($49.45 × x) = ($56.95 × x).

Explanation:

i) Let x be the number of months of Internet Service purchased till the Fast

Internet charges and Quick Internet charges become the same.

ii) Charges for Fast Internet for x months is given by $45 + ($49.45 × x)

iii) Charges for Quick Internet for x months is given by ($56.95 × x)

iv) According to the first statement we will now equate the equations in ii)

and iii) and solve for x.

Therefore, $45 + ($49.45 × x) = ($56.95 × x)

45 + 49.45 x = 56.95 x

Therefore (56.95 - 49.45) x = 45

7.50 × x = 45

Therefore x = 45 ÷ 7.5 = 6