Question

How do I solve these three

Answer 1

below

Explanation:

2(x+5)=3x+1

2x+10=3x+1

10-1=3x-2x

9=x

x=9

3y-4=6-2y

3y+2y=6+4

5y=10

y=10/5

y=2

3(n+2)= 9(6-n)

3n+6=54-9n

3n+9n=54-6

12n=48

n=48/12

n=4

Answer 2

Explanation:

1) 2(x + 5) = 3x + 1

Multiplying each term inside the parenthesis by 2, it becomes

2x + 10 = 3x + 1

Subtracting 2x and - 1 from both sides of the equation

2x - 2x + 10 - 1 = 3x - 2x + 1 - 1

3x - 2x = 10 - 1

x = 9

2) 3y - 4 = 6 - 2y

Adding 4 and 2y to the left hand side and the right hand side of the equation, it becomes

3y + 2y - 4 + 4 = 6 + 4 + 2y - 2y

5y = 10

Dividing the both sides of the equation by 5, it becomes

5y/5 = 10/5

y = 10/2 = 5

3) 3(n + 2) = 9(6 - n)

3n + 6 = 54 - 9n

Subtracting 6 from both sides and adding 9n to both sides of the equation, it becomes

3n + 9n + 6 - 6 = 54 - 6 - 9n + 9n

12n = 48

Dividing both sides of the equation by 12, it becomes

12n/12 = 48/12

n = 4