Answer:
= 15 m/s
Step-by-step explanation:
Considering right side(west) as positive x-axis and south as negative y-axis.
velocity of boat in still water
![v_b=12\hat{i}](https://img.qammunity.org/2021/formulas/physics/college/krp9mo3y9rr7jvofisalgzz4wwn6o7l4ow.png)
velocity of stream
![v_s=-9\hat{j}](https://img.qammunity.org/2021/formulas/physics/college/vjbqstsl5tf3ild1xxntwyhzc0zy3k4bzf.png)
now relative velocity of boat w.r.t. stream
![v_(b/s)=12\hat{i}+9\hat{j}](https://img.qammunity.org/2021/formulas/physics/college/866mhiko5vqtu6l2jsjv0onra0hn6zpktp.png)
this velocity with which ac distance will be covered.
therefore magnitude of
![v_(b/s) =√(12^2+9^2)](https://img.qammunity.org/2021/formulas/physics/college/yuk5w9r4iafamy0qsiihq6zpue4lit0onv.png)
= 15 m/s