Question

Calculate the hoop stress at rupture if the burst (maximum internal) pressure is 136.4 MPa. The PV has a nominal thickness of 4 mm.

Answer 1

`\sigma_x = 1705 MPa`

Step-by-step explanation:

Given data:

Internal pressure = 136.4 MPa

thickness is given as 4 mm

diameter is not given in the question hence we are assuming the diameter of given cylinder to be 100 mm

circumferential stress is given as

`\sigma_x = (P* r)/(t)`

`\sigma_x =  (136.4 * (100)/(2))/(4)`

`\sigma_x = 1705 MPa`