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Chlorine is the most widely used disinfectant for killing pathogens during water treatment. Determine the kilograms of chlorine used daily at a water treatment plant handling 10,000 cubic meters per day of flow at a chlorine dosage of 10 mg/L. [Hint: Multiply the flow rate by the chlorine dosage and make appropriate conversions.] Ans

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Step-by-step explanation:

The given data is as follows.

Flow of chlorine (Q) =
10,000 m^(3)/day

Amount of liter present per day is as follows.


10,000 * 10^(3) l/day

It is given that dosage of chlorine will be as follows.

10 mg/l =
10 * 10^(-6) kg/l

Therefore, total chlorine requirement is as follows.

Total chlorine requirement =
(10,000 * 10^(3)) * (10 * 10^(-6)) kg/day

= 100 kg/day

Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.

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