Question

What is the slope intercept equation of the line that goes through the points (1,-5) and (-3,7)?​

Answer 1

y=-3x-2

Explanation:

The slope intercept equation is y=mx+b. y2-y1/x2-x1 is the equation for the slope. 7-(-5)/-3-1 is -3. Now you have y=-3x+b, you plug in one set of cordinates so you would have 7=-3(-3)+b, 7=9+b, b=-2

y=-3x-2

Hope that helps :)

Answer 2

Explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through the points (1,-5) and (-3,7)

y2 = 7

y1 = - 5

x2 = - 3

x1 = 1

Slope,m = (7 - - 5)/(- 3 - 1) = 12/- 4 =

- 3

To determine the intercept, we would substitute x = - 3, y = 7 and m= - 3,

7 = - 3 × - 3 + c = 9 + c

c = 7 - 9 = - 2

The equation becomes

y = - 3x - 2