Question

When potassium hydroxide and barium chloride react, potassium chloride and barium hydroxide are formed. The balanced equation for this reaction is __________.A. KH + BaCl --> KCl + BaH

B. KOH + BaCl --> KCl + BaOH
C. 2KOH + BaCl₂ --> 2KCl + Ba(OH)₂
D. KOH + BaCl₂ --> KCl₂ + BaOH

Answer 1

Answer: C.

2KOH + BaCl2 => 2KCl + Ba(OH)2

Step-by-step explanation:

There are 2 atoms of O and H in Ba(OH)2 in the product so to balance we put 2 on KOH. Then balance K by adding 2 in KCl to have equal number of atoms for K and Cl in both the reactant and product side. Barium have 1 atom on the reactant and in the product.

Answer 2

The answer to your question is letter C.

Step-by-step explanation:

Reaction

Potassium hydroxide = KOH

Barium chloride = BaCl₂

Potassium chloride = KCl

Barium hydroxide = Ba(OH)₂

KOH + BaCl₂ ⇒ KCl + Ba(OH)₂

Reactant Elements Products

1 K 1

1 Ba 1

2 Cl 1

1 H 2

1 O 2

The reaction is unbalanced

2KOH + BaCl₂ ⇒ 2KCl + Ba(OH)₂

Reactant Elements Products

2 K 2

1 Ba 1

2 Cl 2

2 H 2

2 O 2

Now, the reaction is balanced