Question

Two radioactive nuclides decay by successive first-order processes: (the quantities over the arrows are the half-lives in days). Suppose that Y is an isotope that is required for medical applications. At what time after X is first formed will Y be most abundant?

Answer 1

Step-by-step explanation:

X= 22.5 d

Y=33.0 d

1/life

t max= ln (k2/k1)/(k2-k1)

k1 for XY

½ =.693/k1 =k1=.693/1/2 =.693/22.5 =0.0308

K2= .693/33 =0.021

t max =ln(k2/k1)/(k2-k1) = ln (0.021/0.0308)/(0.021-0.0308) = -0.381/-0.0098 = 38.87755102 days =38.9 days

Answer 2

Hi your question was incomplete because the two half lives were not given, hence I have attached the full version of the question in the attachment below.

Answer:

38.9 Days

Step-by-step explanation:

Please refer to the attachment below for explanation.