Answer:
24.2% students received grades with z-scores between 0.15 and 0.85
Explanation:
We are given the following in the question:
The grades of a benchmark test for North High School were normally distributed.
WE have to find the percentage of students that received grades with z-scores between 0.15 and 0.85.
Formula:
![z_(score) = \displaystyle(x-\mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/high-school/pad6rntb722qswc0kw4hmbstruityvpgp4.png)
P(score between 0.15 < z < 0.85)
![P(0.15 \leq z \leq 0.85)\\\\= P(z \leq 0.85) - P(z \leq 0.15)\\\\\text{Calculating the value from standard normal z-table}\\\\= 0.802 - 0.560 = 0.242 = 24.2\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/30klmmk84acq1dqf380u3uy5m9zgcob8ep.png)
24.2% students received grades with z-scores between 0.15 and 0.85