Question

What is the mass % of ammonium chloride in a 1.73 M ammonium chloride aqueous solution at 20 °C?

Answer 1

The question is incomplete, here is the complete question:

What is the mass % of ammonium chloride in a 1.73 M ammonium chloride aqueous solution at 20 °C? The density of the solution is 1.0257 g/mL

Answer: The mass percent of ammonium chloride in solution is 9.03 %

Step-by-step explanation:

We are given:

Molarity of ammonium chloride solution = 1.73 M

This means that 1.73 moles of ammonium chloride is present in 1 L or 1000 mL of solution.

• To calculate the mass of solution, we use the equation:

`\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}`

Density of solution = 1.0257 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

`1.0257g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.0257g/mL* 1000mL)=1025.7g`

• To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Moles of ammonium chloride = 1.73 moles

Molar mass of ammonium chloride = 53.5 g/mol

Putting values in above equation, we get:

`1.73mol=\frac{\text{Mass of ammonium chloride}}{53.5g/mol}\\\\\text{Mass of ammonium chloride}=(1.73mol* 53.5g/mol)=92.6g`

• To calculate the mass percentage of ammonium chloride in solution, we use the equation:

`\text{Mass percent of ammonium chloride}=\frac{\text{Mass of ammonium chloride}}{\text{Mass of solution}}* 100`

Mass of solution = 1025.7 g

Mass of ammonium chloride = 92.6 g

Putting values in above equation, we get:

`\text{Mass percent of ammonium chloride}=(92.6g)/(1025.7g)* 100=9.03\%`

Hence, the mass percent of ammonium chloride in solution is 9.03 %