Question

A projectile is launched at a diagonal angle and is in the air for 17.5 seconds. How long does it take the projectile to reach its apex?

Answer 1

`t_h=8.75\ s`

Step-by-step explanation:

For a projectile the total time it stays in the air is called the flight time. The path traced during a projectile motion is parabolic with symmetry of time and distance.

Given that the projectile having a flight time of 17.5 seconds, will reach the top point in half of the flight time taken by it:

So,
`t_h=(T)/(2)`

`t_h=(17.5)/(2)`

`t_h=8.75\ s` is the time by the end of which the projectile will be at its apex having the vertical component of velocity as zero.

Do note that during a projectile analysis we neglect the air resistance due to which we have a constant horizontal component of the velocity and the vertical component of the velocity varies under the influence of gravity. The vertical velocity at the top becomes zero.