Question

A pure organic amide product (2.85 g) which has a molecular weight of 285.34 g/mol was fully dissolved in 20mL of the boiling solvent, hexanes. This organic amide product then underwent a recrystallization when the solvent was cooled to 0° C. The recrystallized organic product (2.62 grams) was obtained after vacuum filtration. What is the solubility of the organic amide product in the solvent, hexanes, at 0° C?

Answer 1

The solubility of the organic amide product in the solvent hexane is 0.0403 moles/L at 0° C

Step-by-step explanation:

When 2.85gm dissolved in 20ml of boiling solvent

After re crystallization 2.62gm was obtained

so, that the dissolved amount at 0° C is

2.85 - 2.62

= 0.23 gm in 20ml hexane

Mole of amide
`= (0.23)/(285.34) moles`

Solubility
`= (0.23)/(285.34) * (1000)/(20)`

= 0.0403 moles/L

Therefore, the solubility of the organic amide product in the solvent hexane is 0.0403 moles/L at 0° C