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A line passes through the point (4, –6) and has a slope of Negative three-fourths. Which is the equation of the line?

A y = negative three-fourths x minus 3
B y = negative three-fourths x minus 6
C y = negative 3 x minus three-fourths
D y = negative 6 x minus three-fourths

2 Answers

6 votes

Answer:

the answer is A

Explanation:

Hope this helps!

User Andrew Halloran
by
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4 votes

Option A

The equation of line is
y = (-3)/(4)x - 3

Solution:

Given that line passes through the point (4, –6) and has a slope of Negative three-fourths

Given point is (x, y) = (4, -6)


slope = (-3)/(4)

The equation of line passing through point (x, y) and slope "m" is given as:

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Substitute (x, y) = (4, -6) and
m = (-3)/(4) in eqn 1


-6 = (-3)/(4) * 4 + c\\\\-6 = -3 + c\\\\c = -6 + 3\\\\c = -3

The required equation of line is given as:


\text{ Substitute } m = (-3)/(4) \text{ and } c = -3 \text{ in eqn 1 }


y = (-3)/(4)x - 3

Thus the equation of line is found

User AhmadAssaf
by
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