Question

The width of a rectangle is 6 t minus 4.5 feet and the length is 4.5 t plus 9 feet. Find the perimeter of the rectangle. help plzz &thxs :)

Answer 1

The perimeter of the rectangle can be represented as:

⇒
`(21t+27)\ ft`

Explanation:

Given :

Width of the rectangle =
`(6t-4.5)\ ft`

Length of the rectangle =
`(4.5t+9)\ ft`

To find the perimeter of the rectangle.

Solution:

The perimeter of a rectangle is given as :

⇒
`2(l+w)`

where
`l` represents length of the rectangle and
`w` represents the width of the rectangle.

Plugging in the given data of length and width to find the perimeter of the rectangle.

⇒
`2(6t+4.5+4.5t+9)`

Adding like terms.

⇒
`2(6t+4.5t+4.5+9)`

⇒
`2(10.5t+13.5)`

Using distribution

⇒
`(21t+27)\ ft`

Thus, perimeter of the rectangle can be represented as:

⇒
`(21t+27)\ ft` (Answer)