Answer:
Yes, the unknown substance is the liquid ethylene glycol.
Step-by-step explanation:
Here the density of the unknown substance is 69.22lb/f and the density of ethylene glycol, the liquid used in antifreeze is 1.1088g/ml
We know, 1g = 0.0022lb
1ml=
![3.531 * 10^(-5) ft^3](https://img.qammunity.org/2021/formulas/chemistry/middle-school/k43bcb4n4mvwbdqgi4p567916pt4w8dcj1.png)
Therefore, 1g/ml = 62.428
![lb/ft^3](https://img.qammunity.org/2021/formulas/chemistry/middle-school/rx7sf10g6xbjt3ccgm7ehwijh2ve200lwx.png)
Since, the density of ethylene glycol = 1.1088g/ml
= 1.1088
62.428
![lb/ft^3](https://img.qammunity.org/2021/formulas/chemistry/middle-school/rx7sf10g6xbjt3ccgm7ehwijh2ve200lwx.png)
= 69.22
![lb/ft^3](https://img.qammunity.org/2021/formulas/chemistry/middle-school/rx7sf10g6xbjt3ccgm7ehwijh2ve200lwx.png)
When the density of ethylene gas is converted from g/ml unit to
unit, it is found to have the same value (69.22)Therefore, the unknown substance here is liquid ethylene glycol.