Question

A 2.40 μC charge is subject to a 3.00 mN force due to an Electric Field. What is the magnitude of the Electric Field at the location of the charge?

Answer 1

The magnitude of the electric field at the location of the 2.40 μC charge is 1250 N/C.

Step-by-step explanation:

The magnitude of the electric field at the location of the 2.40 μC charge can be calculated using the equation:

E = F / q

Where E is the electric field, F is the force, and q is the charge.

In this case, the force is given as 3.00 mN, which is equal to 0.003 N, and the charge is 2.40 μC, which is equal to 2.40 x 10^-6 C. Plugging these values into the equation, we get:

E = (0.003 N) / (2.40 x 10^-6 C) = 1250 N/C

Therefore, the magnitude of the electric field at the location of the charge is 1250 N/C.