Question

Draw the structure of the starting material needed to make 2-methylhept-3-yne using sodium amide in liquid ammonia, followed by 1-bromopropane. The starting hydrocarbon must have no more than five carbons. 1) NaNH2, NH3(l) 2) CH3CH2CH2Br + NaBr

Answer 1

see explanation below

Step-by-step explanation:

This question I already answer it to another person, so I just gonna do the same thing here.

the Starting material would have to be the following:

CH3 - CH(CH3) - C ≡ CH

When this reactant, is in presence of NaNH2, the NH2 substract the Hydrogen from carbon 1, and then, this will attack as nucleophyle to the carbon 1 of the bromopropane and formed the desired product. The mechanism is as following in the picture.