Question

The width of a rectangle is 4 1/6 feet, and its area is 35 square feet. What is the perimeter of this rectangle?

Answer 1

The perimeter of rectangle is 25.13 feet

Solution:

Given that,

width of a rectangle =
`4(1)/(6) \text{ feet }`

Convert the mixed fraction to improper fraction

`\rightarrow 4(1)/(6) = (6 * 4 + 1)/(6) = (25)/(6)`

Therefore,

`\text{width of rectangle } = (25)/(6) \text{ feet }`

Area of rectangle = 35 feet

The area of rectangle is given by formula:

`area = length * width`

Substituting the given values, we get

`35 = length * (25)/(6)\\\\length = 35 * (6)/(25) = (42)/(5)`

Thus we get,

`\text{length of rectangle } = (42)/(5) \text{ feet }`

The perimeter of rectangle is given as:

perimeter = 2(length + width)

`perimeter = 2((42)/(5) + (25)/(6))\\\\perimeter =2(8.4+4.167)\\\\perimeter = 2(12.567)\\\\perimeter = 25.13`

Thus perimeter of rectangle is 25.13 feet