Answer:
135.73 ounces of a silver alloy that costs $5.50 per ounce should be mixed.
Explanation:
Given:
A silver alloy that costs $5.50 per ounce should be mixed with one that costs $7.00 per ounce to make a new 30 ounce alloy that costs $6.40 per ounce.
Now, to find the ounces of silver alloy.
Let the silver costs $5.50 per ounce be
![x.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mmi228653dkvma4dszwy75q6dvkduzr4zg.png)
And the silver costs $7.00 per ounce be
![y.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gcglyt0bd2c9ftxzcnzvksi0ue28vql4ne.png)
So, the total ounce make a new alloy:
....(1)
Now, the total costs of silver alloy:
![5.50x+7y=6.4](https://img.qammunity.org/2021/formulas/mathematics/high-school/cr1iso5bcksyzktfzhcddeudkhdwrimnl5.png)
Putting the value of
from equation (1) in the place of
:
![5.50x+7(30-x)=6.4](https://img.qammunity.org/2021/formulas/mathematics/high-school/1ixzt3xhxtw0rsau2knpc2j7qirb8yxkk1.png)
![5.50x+210-7x=6.4](https://img.qammunity.org/2021/formulas/mathematics/high-school/h0oq0tiwxa2tuekze79jm20ptp8tch8a3p.png)
![-1.5x+210=6.4](https://img.qammunity.org/2021/formulas/mathematics/high-school/sorgvxln8dv08oweyjbaj65ek3s8c3txls.png)
Subtracting both sides by 210 we get:
![-1.5x=-203.6](https://img.qammunity.org/2021/formulas/mathematics/high-school/f77mp4cyfisnen9klqxibihk1pp3ndlppb.png)
Dividing both sides by -1.5 we get:
![x=135.73](https://img.qammunity.org/2021/formulas/mathematics/high-school/i4bo0akcjr11xuypqwelseuuhy9ahqortx.png)
Therefore, 135.73 ounces of a silver alloy that costs $5.50 per ounce should be mixed.