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A car initially going 61 ft/sec brakes at a constant rate (constant negative acceleration), coming to a stop in 7 seconds.

a) Graph the velocity from t = 0 to t = 7.
(b) How far does the car travel?
(c) How far does the car travel if its initial velocity is doubled, but it brakes at the same constant rate?

User Mkubaczyk
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1 Answer

4 votes

Answer:

See the attachment below for the graphics in part (a)

The initial velocity for this time interval is u = 61ft/sec and the final velocity is 0m/s because the car comes to a stop.

This a constant acceleration motion considering the given time interview over which the brakes are applied. So the equals for constant acceleration motion apply here.

Step-by-step explanation:

The full solution can be found in the attachment below.

Thank you for reading. I hope this post is helpful to you.

A car initially going 61 ft/sec brakes at a constant rate (constant negative acceleration-example-1
User Mojtaba Nava
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