Question

Calculate the wavelength of the photon that would be absorbed or emitted. Round your answer to 3 significant digits.

Answer 1

This is an incomplete question, the image for the given question is attached below.

Answer : The wavelength of photon would be absorbed,
`3.06* 10^(-7)m`

Explanation :

From the given diagram of energy we conclude that,

Energy at ground state, A = 400 zJ

Energy of 2nd excited state, C = 1050 zJ

Now we have to calculate the energy of the photon.

`E=E_c-E_A`

`E=(1050-400)zJ= 650zJ=650* 10^(-21)J`

Now we have to calculate the wavelength of the photon.

Formula used :

`E=h* \\u`

As,
`\\u=(c)/(\lambda)`

So,
`E=h* (c)/(\lambda)`

where,

E = energy of photon =
`650* 10^(-21)J`

`\\u` = frequency of photon

h = Planck's constant =
`6.626* 10^(-34)Js`

`\lambda` = wavelength of photon = ?

c = speed of light =
`3* 10^8m/s`

Now put all the given values in the above formula, we get:

`650* 10^(-21)J=(6.626* 10^(-34)Js)* ((3* 10^(8)m/s))/(\lambda)`

`\lambda=3.06* 10^(-7)m`

Therefore, the wavelength of photon would be absorbed,
`3.06* 10^(-7)m`